Topic: Argh, this is annoying me. [maths inside!!]

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Posted at January 27, 2016, 11:14 am:

I've been stuck on these questions for ages, it's on conditional probability.

I don't want the straight answer, just any help.

question: A depleted pack of cards contains 8 black cards and 10 red cards. 2 of the black cards and 3 od the red cards are aces. George picks a card at random. Find the probablity that it is

a) Not an ace, given that it is red p(A'|R)
b) Red, given that it is not an ace p(R|A')

I know I should use the formula p(B|A) = p(A+B)/P(A)

and it's confusing me, and I don't have a clue why : /

so if anyone can point me in the direction of what i should be doin would be great.

++to anyone that helps

Original of the message was taken from http://www.sputnikmusic.com/forums/

Replies:

use bayes theorem

isn't A just 7/18?

A depleted pack of cards contains 8 black cards and 10 red cards.

Yes, but I have to use the formula logically with the question, so the...

1.

I don't know, it's what my teacher gave us : / 2.

a) Not an ace, given that it is red p(A'|R) p(a'|R)= ( P(R|a')*P(a') ...

Ew data management.

1.

hmm i'm sure i've used it before and it worked : / i'm probably just ...

logically, if there are 10 red cards, and 3 of them are aces, your cha...

i hate math

a) Not an ace, given that it is red p(A'|R): There are 10 red cards a...

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